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tennis2007.org"s solved example with equipment to find what is the probability of acquiring 1 Head in 5 coin tosses. P(A) = 31/32 = 0.97


for 1 Head in 5 Coin FlipsAtleast 1 HeadExactly 1 Head
Total occasions n(S)3232
Success events n(A)315
Probability P(A)0.970.16

The over probability that outcomes applicable come the below questions too.
Probability that flipping a coin 1 times and getting 5 head in a row Probability of gaining 5 head when flipping 1 coins together A coin is tossed 1 times, discover the probability that at least 5 are head? If you flip a fair coin 1 time what is the probability the you will certainly get exactly 5 head? A coin is tossed 1 times, what is the probability that getting specifically 5 head?

The ratio of successful events A = 31 to the total variety of possible combinations of a sample space S = 32 is the probability that 1 head in 5 coin tosses. Users may refer the listed below solved example work with steps to learn how to uncover what is the probability of obtaining at-least 1 head, if a coin is tossed 5 times or 5 coins tossed together. Users might refer this tree diagram to learn just how to discover all the possible combinations of sample space for flipping a coin one, two, 3 or 4 times.

You are watching: Probability of at least one heads

SolutionStep by action workoutstep 1 uncover the total feasible events that sample space S S = HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH, TTTTT S = 32 step 2 find the supposed or successful events A A = HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH A = 31 action 3 find the probability P(A) = successful Events/Total events of Sample room = 31/32 = 0.97 P(A) = 0.97 0.97 is the probability of getting 1 Head in 5 tosses.


The ratio of successful events A = 5 to total number of possible combine of sample space S = 32 is the probability of 1 head in 5 coin tosses. Users might refer the below detailed solved instance with action by step calculation come learn just how to discover what is the probability of getting precisely 1 head, if a coin is tossed 5 times or 5 coins tossed together.

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Solution : step by step workout action 1 find the total feasible combinations of sample room S S = HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH, TTTTT S = 32 action 2 uncover the supposed or successful events A A = HTTTT, THTTT, TTHTT, TTTHT, TTTTH A = 5 step 3 discover the probability P(A) = effective Events/Total events of Sample an are = 5/32 = 0.16 P(A) = 0.16 0.16 is the probability that getting precisely 1 Head in 5 tosses.