for this reason I recognize that if you role a typical pair the dice, your opportunities of acquiring Snake eyes (double 1s) is \$1\$ in \$36\$. What I"m not sure of is just how to carry out the tennis2007.orgematics to number out your opportunities of rolling snake Eyes at least once throughout a collection of rolls. I know if I role the dice \$36\$ times it won"t lead to a \$100\%\$ chance of rolling snake Eyes, and while i imagine it"s in the upper nineties, I"d favor to figure out exactly how i can not qualify it is.

You are watching: Odds of rolling snake eyes twice in a row

The probability that hitting it at least once is \$1\$ minus the probabilty the never hitting it.

Every time you roll the dice, you have a \$35/36\$ opportunity of not hitting it. If you role the dice \$n\$ times, then the only case where you have actually never hit it, is once you have actually not hit it every single time.

The probabilty of no hitting v \$2\$ rolls is for this reason \$35/36 imes 35/36\$, the probabilty of not hitting v \$3\$ roll is \$35/36 imes 35/36 imes 35/36=(35/36)^3\$ and so ~ above till \$(35/36)^n\$.

Thus the probability the hitting the at the very least once is \$1-(35/36)^n\$ where \$n\$ is the number of throws.

After \$164\$ throws, the probability of hitting the at least once is \$99\%\$

re-superstructure
point out
follow
edited Oct 4 "18 at 13:00

J. M. Ain't a tennis2007.orgematician
reply Oct 3 "18 at 13:19

b00n heTb00n heT
\$endgroup\$
1
33
\$egingroup\$
The various other answers describe the basic formula because that the probability of never ever rolling snake eyes in a collection of \$n\$ rolls.

However, you additionally ask specifically about the instance \$n=36\$, i.e. If you have a \$1\$ in \$k\$ chance of success, what is your chance of gaining at the very least one success in \$k\$ trials? It turns out the the answer come this inquiry is quite similar for any reasonably large value that \$k\$.

It is \$1-ig(1-frac1kig)^k\$, and also \$ig(1-frac1kig)^k\$ converges come \$e^-1\$. So the probability will certainly be about \$1-e^-1approx 63.2\%\$, and also this approximation will certainly get better the larger \$k\$ is. (For \$k=36\$ the genuine answer is \$63.7\%\$.)

share
cite
monitor
answered Oct 3 "18 at 13:40

particularly LimeEspecially Lime
\$endgroup\$
include a comment |
8
\$egingroup\$
If you role \$n\$ times, climate the probability the rolling snake eyes at least once is \$1-left(frac3536 ight)^n\$, together you either roll snake eyes at least once or not at every (so the probability of these two events should amount to \$1\$), and also the probability of never ever rolling line eyes is the same as requiring the you roll one of the other \$35\$ possible outcomes on every roll.

share
point out
monitor
answer Oct 3 "18 at 13:22
Sam StreeterSam Streeter
\$endgroup\$
include a comment |

Thanks for contributing an answer to tennis2007.org Stack Exchange!

Please be certain to answer the question. Carry out details and also share her research!

But avoid

Asking because that help, clarification, or responding to other answers.Making statements based upon opinion; ago them increase with referrals or personal experience.

Use tennis2007.orgJax to style equations. tennis2007.orgJax reference.

To find out more, check out our advice on writing great answers.

See more: 10 Year Old Cat Was Doused With Liquid D Is Palmolive Dish Soap Safe For Cats ?

Draft saved

authorize up utilizing Email and Password
submit

### Post as a guest

surname
email Required, but never shown

### Post together a guest

name
email

Required, but never shown

## Not the prize you're spring for? Browse other questions tagged probability dice or ask your very own question.

Featured on Meta
associated
2
What is the probability of rolling at the very least one \$7\$, \$11\$, or doubles in one experiment consist of of 2 rolls?
1
Yahtzee Bar game
0
What space the opportunities of drawing 2 shotguns in Zombie Dice in this situation?
4
how do you calculation the amount of combine of 1000 dice rolls?
2
Expected number of dice rolls for a succession of dice rolls ending at snake eyes
1
dice odds that a certain number roll at least once
0
chances of rojo doubles on 2d6 vs 1d4 and also 1d6.
1
Probability of rolling at the very least one line eyes (pair of 2 ones) with four dice, rolling 3 time
warm Network questions much more hot inquiries

question feed