A ray of sunlight casts a shadow of a flagpole on the ground at an angle of depression of 58 degrees. If the length of the shadow is 3m shorter than the height of the flagpole, find the height of the flagpole.

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I"m confused about the given problem above because I can"t determine yet the length of the shadow, and also I"m stuck at the angle of depression, in which I supposed that it has to be the angle of elevation instead.

My solution:

$sinleft(58^circ ight)=fracxx-3$

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trigonometry
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Folshort
edited Jan 22 "18 at 22:08
Xtravagant
asked Jan 22 "18 at 21:42
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First, we draw a flagpole, $x$m long. Then we draw a shadow that is $x-3$m long. Then the sun ray which casts the shadow connects the TOP of the pole and TOP of the shadow. This means the angle formed by the hypotenuse (the sun ray) and the shadow is $58^o$. Now we have $ an 58^o=fracxx-3$, giving us $x an 58^o-3 an 58^o=x$. We bring $x$ to one side, having $xleft( an 58^o-1 ight)=3 an 58^o$. $x=7.997...=8.00left(3sf ight)$.
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Folshort
edited Feb 19 "20 at 8:48
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wuyudi
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answered Jan 22 "18 at 21:52
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